► JEST 2012, Question Paper, Download, Answer Key, Pdf File 19 February - Discuss the Answers
Home
»
2012
»
Download
»
JEST
»
Question Paper
»
JEST 2012, Question Paper, Download, Answer Key, Pdf File 19 February - Discuss the Answers
Would you like to subscribe through facebook
JEST 2012 Question Paper With Answer Key Clik Here to Download
JEST 2012 answer key Clik Here to Download
Comment the Detailed answers of the questions below. Do not comment the answers you are not sure.
JEST 2012 Question Paper Free Download pdf file, question papers JEST 2012 for physics, free downloadablephysics JEST exam papers, 1 physics model questions, today JEST paper, todays JEST question, todays JEST exam, answer for JEST 2012, answer key JEST 2012 JEST 2012 solved papers, JEST 2012 question pattern, JEST 2012 exam syllabus, JEST 2012 syllabus ec, JEST 2012 question paper, JEST question papers download JEST Result JEST 2012Answers Key - Solutions, JEST 2012 cutoff JEST2012 physics paper solved key
Posted by our guest writer S . If there is any content violations Report the Administrator by clicking "Report Problem".
Labels:
2012
,
Download
,
JEST
,
Question Paper
(X)
The net electrical charge of the semiconductor material is zero.
ReplyDeleteQuestion no. 35
ReplyDeleteans. 1
Part B
ReplyDeleteprobability ans 2/9
distance betwetn latice plane ans 4 A
resistor ratio ans N^2
angle of refractd beam ans 56.7
Rms error 3.3%
period of pendulum ans 2T/sprt5
ground state of 5 identical particles 5hw
orthogonal ans -exp(-i phi) cosx +sinx
N.N matrix ans one eigen value N Other 0
canonical pair ans q2,-p2
wave fn ans parity operator
efficency ans 1
electic fild for r>R ans -BR2/2r theata
PART A
electic fild ans -vB(14j+7k)
integral ans e-1/e
temp aftr compres ans 887
series converges to pi/4
magnetic field in othr inertial frame E2=B2
Change in entropy ln(T1+T2/2SQRT(T1T2))
********three mark question*******
ReplyDeleteconsider a particle of mass m moving inside a two-dimensional square box: ans-(c)5(hcut)^2/(2mL^2)
a monoatomic ideal gas at 17 degree: ans- (d) 887 degree
an observer in an inertial frame finds that: ans- (b) E.B= 0
a magnetic field B=B0(i+2j-4k): ans-(d) E=-v0B0(14j+7k)
define (sigma)x = (f'+ f) & (sigma)y = (f'- f): ans-(b) 2f'f-1
an electric in a region is given by E(x,y,z): ans-(c) 13,1,6
consider an ideal gas of mass m at temperature T1: ans-(a)
consider the bohr model of the hydrogen atom: ans-(d)
********one mark question******
the ground state energy of 5 identical spin-1/2: ans-(b)
efficiency of perfectly reversible: ans- (d) 1
a point charge +q placed at (0,0,d): ans- (d)
what is the value of the series: ans-(d) 1
the second order maximum in the diffraction: ans-(c) 4 Ang
the spatial part of a two-electron state: ans-(c)
the ratio of maximum to minimum resistance: ans-(b)
the wave function of a free particle in one dimension: ans-(d)
the net charge of a n-type: ans-(b)
the length and radius RMS error: ans-(a)
when unpolarised light is incident: ans- (a)
if the co-ordinate q and the momentum p : ans-(c)
the quantum state sin x... : ans-(d)
the binding energy of positronium: ans-(a)
for an N*N matrix: ans-(d)
an unbiased die : ans-(b)
a cube has a constant electric pot. V : ans-(a)
a girl measures the period of simple pendulum: ans-(c)
a sodium atom in the first excited...corresponding line-width: ans-(b)
consider a particle of electric charge e... its trajectory: ans-(a) or (c)
R series..
ReplyDelete3. d
5. d
9. c
10. a
12. b
14. c
16. c
17. c
20. b
22. 0
24. a
25. d
26. c
27. c
29. b
30. d
31. d
32. b
34. d
35. a
36. d
37. b
39. b
42. c
43. d
45. d
47. b
48. a
49. a
50. c
R series..
ReplyDelete3. d
5. d
9. c
10. a
12. b
14. c
16. c
17. c
20. b
22. 0
24. a
25. d
26. c
27. c
29. b
30. d
31. d
32. b
34. d
35. a
36. d
37. b
39. b
42. c
43. d
45. d
47. b
48. a
49. a
50. c
PLEASE dont just tell the question no and the key since there are the series of booklet. It is better to tell the answer with some hint.
ReplyDeleteplease do not post according to question no. because there are three sets available...try to mention questions..
ReplyDeleteSet p
ReplyDelete5.d
6.c
10.d
12.a
13.c
14.c
17.c
18.b
20.a
22.b
25.a
27.b
28.d
29.d
31.c
32.b
33.d
34.d
35.d
36.c
39.c
42.b
43.c
44.b
48.a
49.d
50.d
any corrections . Pls comment on this key
answer of 34 is not correct...the answer is c..that is magnitude of the field is zero,,,,,
Deleteseries R 3D,9D,10B,14C,17C,19B,25D,31D,34C,35B(NT SURE),37B,44A,47B,48C,49C..PLZ CHECK N CORRECT IF RQURD.
ReplyDeleteans for Q-set jest-19th feb 2012
ReplyDelete2)a (May Be)
4)d
5)c (May Be)
6)c
9)d
10)c (May Be)
11)a
15)a
19)c
20)b
21)a
22)b
23)a
27)b
28)d
29)c
30)d
33)c
34)b
35)d
37)c
38)c
39)b
41)b
43)b
46)c
47)d
49)d
Q49 ANSWER IS d series q
ReplyDeleteQuestion no. 27
ReplyDeleteans. C
no.31
ans. C
no. 32
ans. B
no.34
ans. A
no. 36
ans. C
no.40
ans. B
no.42
ans. C
no.44
ans. C
no. 49
ans. D
QUESTION NO. 1
ReplyDeleteANS. 887
QUESTION NO. 2
ANS. E.B=0
QUESTION NO. 4
ANS. X2/2-SQRT(2)XTANH(SQRT(2)X)
QUESTION NO. 5
ANS. E=-VoBo(14j+7k)
QUESTION NO. 6
ANS. BECOMES APERIODIC
QUESTION NO. 7
ANS. Rf=Ro/2
QUESTION NO. 10
ANS. ac
QUESTION NO. 11
ANS. 3h2/2ML2
QUESTION NO. 12
ANS. 2mCpln(T1-T2)/2SQRT(T1T2)
QUESTION NO. 13
ANS. 0.9c
QUESTION NO. 17
ANS. 45,6,1
QUESTION NO. 18
ANS. 1
QUESTION NO. 20
ANS. INFINITE
QUESTION NO. 23
ANS. Vo/2(1-EXP(-t/2RC))
QUESTION NO. 24
ANS. ONVERGES TO UNITY
QUESTION NO. 25
ANS. h=k=l
QUESTION NO. 26
ANS. MOVES WITH A CONSTANT DECELERATION
QUESTION NO. 28
ANS. 1
QUESTION NO. 32
ANS. N2
QUESTION NO. 33
ANS. HAMILTONIAN
QUESTION NO. 34
ANS. q/16PIEoD2
QUESTION NO. 35
ANS. 1
QUESTION NO. 36
ANS. 4 A
QUESTION NO. 40
ANS. ZERO
QUESTION NO. 41
ANS. 3.3%
QUESTION NO. 42
ANS. 23.3
QUESTION NO. 43
ANS. >>300K
QUESTION NO. 44
ANS. 1/9
QUESTION NO. 45
ANS. 0
QUESTION NO. 46
ANS. 2T/SQRT(5)
QUESTION NO. 48
ANS. 13.6/2
QUESTION NO. 49
ANS. ONE EIGEN VALUE=N, THE OTHER=0
QUESTION NO. 50
ANS. 1.7 * 10(6) HZ
anybody have computer science answer key....
ReplyDelete@Anonymous
ReplyDeleteqn 50 of p series ans is"b"
vishal sir,23 17 etc are correct?? i think dey need correction.:(
ReplyDelete@evan
ReplyDeletehello evan ,
please check quest. 39 of r series booklet....unpolarised light....
its answer is (b) 33.4 degree
not 56.7 degree
please give me a hint about quest. 4 (changes sign underexchnage of x & y)
, quest. 29 (ground state of harmonic oscillator)
quest 38(rms error)
urs all other questions are perfect.
best of luck
@prashant
ReplyDeletesir can u jst cmment on q2,18,22,10,24,23 set r.. plzz
anyone set r,perfect answers for part b q28,26,46,48..
ReplyDelete@prashant for one dimensional harmonic oscillator he has given 5 particles and he said spin - 1/2
ReplyDeleteso they are fermions
he has not mentioned the spin state
so 2 particles for one state so,
(2hw/2+6hw/2+5hw/2)=13hw/2
@Anonymous
ReplyDeleteques (2) entropy of the system (a)
ques (10) simple pendulum (c)
ques (23) infinte series (c)
ques (24) bcc crystal (a)
@Anonymous
ReplyDeleteset r
(28) small magnet(a)
(46) debye temp. (a)
(48) potential of cube (a)
can anyone answer the question 25 of set Q in which we have to find the entropy of a two level system with energy E1 and E2 each with degeneracy g1 and g2 , and probability p1 and p2
ReplyDeleteseries R
ReplyDeleteQ1...(b)
Q3...(d)
Q4...(c)
Q5...(d)
Q6...(b)
Q7...(d)
Q9...(c)
Q10...(b)
Q12...(b)
Q14...(c)
Q15...(a)
Q16...(c)
Q17...(c)
Q21...(b)
Q22...(a)
Q23...(c)
Q24...(a)
Q26...(a)
Q27...(c)
Q28...(d)
Q29...(d)
Q30...(d)
Q31...(d)
Q33...(c)
Q34...(c)
Q36...(d)
Q37...(b)
Q39...(a)
Q40...(c)
Q42...(c)
Q43...(d)
Q44...(a)
Q45...(d)
Q46...(a)
Q47...(a)
Q48...(a)
Q49...(c)
megharaj
ReplyDeleteall the ans quoted here for spatial part of two-electron state is (c) which wrong, correct ans is (d) becoz itz a symmetric state.
Can anyone please tell me that when is the result expected & hw much marks is the good enough to get admission..kindly tell soon
ReplyDelete@Nagendra Shiwakoti Ans to probability question is 1/9 because they ask for positive diff. between two numbers.
ReplyDeleteSET- R
ReplyDeleteQ.No
1:- ( )
2:- ( )
3:- (D)
4:- (C)
5:- (D)
6:- ( )
7:- ( )
8:- (B), here put value of w.f. in S.E. and take energy as additive constant.
9:- (D), Since F= q(E+v*B)=0 => E=-(V*B).
10:- ( )
11:- ( )
12:- (B)
13:- (C)
14:- (C), Since for Electrostatic field Curl of E = 0
15:- (A)
16:- (C), (5/V)=5micro Sec/Sqrt(1-V^2/C^2)
17:- (C)
18:- ( )
19:- (B)
20:- ( )
21:- ( )
22:- (A)
23:- (C)
24:- (A)
25:- (D), First reduce the circuit using thevenin's theorem after that solution is straight forward.
26:- (C), Electic force >>>> gravitational force.
27:- ( )
28:- ( )
29:- (D), fill up to n=4 energy levels because H.O energy levels are non degenerate.
30:- (D), Efficiency= 1-T2/T1 and t2=0 here.
31:- (D)
32:- (D), A2-B2=(A-B)(A+B) then first term becomes exp(X) & 2nd term becomes exp(-X).
33:- (C)
34:- (C)
35:- (B)
36:- (D)
37:- (B)
38:- ( )
39:- ( )
40:- ( )
41:- ( )
42:- (C)
43:- (D)
44:- (A)
45:- (D)
46:- (A)
47:- (A)
48:- (A)
49:- (C)
50:- ( )
Latest answer key with question paper http://physics43.files.wordpress.com/2012/03/jest-2012-question.pdf
ReplyDeleteThe JEST 2012 Question paper and answer key for the JEST 2012 (e.g P-series) is available for verification.
ReplyDeleteIf you have any objection on the published answer key, please write to jest12 @physics .iisc. ernet. in with valid arguments before 10.00 am on or before 5th March 2012."
The JEST 2012 Question paper and answer key for the JEST 2012 (e.g P-series) is available for verification.
ReplyDeleteIf you have any objection on the published answer key, please write to jest12 @physics .iisc. ernet. in with valid arguments before 10.00 am on or before 5th March 2012."
http://physicskerala.blogspot.in/2011/03/jest-2011-results-published-at.html
ReplyDeleteresults are expected to be on 16th of this month
ReplyDeleteand the cut off may be 30
and to get admission one must get a rank below 150